Q1. A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.
Ans.
Number of tickets sold on first day = 1,094
Number of tickets sold on second day = 1,812
Number of tickets sold on third day = 2,050
Number of tickets sold on fourth day = 2,751
Total tickets sold = 1094 + 1812 + 2050 + 2751 = 7,707
Hence total number of tickets sold on all the four days = 7,707 tickets.
Q2. Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?
Ans.
Runs to achieve = 10,000
Runs scored = 6,980
Runs required = 10,000 - 6980 = 3,020
Hence he needs 3,020 more runs.
Q3. In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,700 votes. By what margin did the successful candidate win the election?
Ans.
Number of votes secured by successful candidates = 5,77,500
Number of votes secured by his nearest rival = 3,48,700
Margin between them
= 5,77,500 - 3,48,700
= 2,28,800
Hence, the successful candidate won by a margin of 2,28,800 votes.
Q4. Kirti Bookstore sold books worth ₹2,85,891 in the first week of June and books worth ₹4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?
Ans.
Books sold in first week = 2,85,891
Books sold in second week = 4,00,768
Total books sold
= 2,85,891 + 4,00,768
= 6,86,659
Since 4,00,768 > 2,85,891
Therefore sale of second week is greater than that of first week.
Books sold in second week = 4,00,768
Books sold in first week = 2,85,891
More books sold in second week
= 4,00,768 - 2,85,891
= 1,14,877
Therefore 1,14,877 more books were sold in second week.
Q5. Find the difference between the greatest and the least number that can be written using the digits 6, 2, 7, 4, 3 each only once.
Ans.
Greatest five-digit number that can be written using digits 6,2,7,4,3
= 76432
Smallest five-digit number that can be written using digits 6,2,7,4,3
= 23467
Difference
= 76432 - 23467
= 52965
Hence the difference = 52965.
Q6. A machine, on an average, manufactures 2,825 screws a day. How many screws did it produce in the month of January 2006?
Ans.
Number of screws manufactured in one day = 2,825
Number of days in the month of January = 31 days
Hence the number of screws produced in January 2006
= 2,825 x 31
= 87,575
Hence the machine produced 87,575 screws in the month of January.
Q7. A merchant had ₹78,592 with her. She placed an order for purchasing 40 radio sets at ₹1,200 each. How much money will remain with her after the purchase?
Ans.
Cost of one radio = ₹ 1200
Cost of 40 radios = 1200 x 40 = ₹ 48,000
Total amount of money which merchant had = ₹ 78,592
Money spent by her = ₹ 48,000
Money left with her = ₹ 78,592 - ₹ 48,000
= ₹ 30,592
Therefore ₹ 30,592 will remain with her after the purchase of 40 radios
Q8. A student multiplied 7236 by 65 instead of multiplying by 56. By how much was his answer greater than the correct answer?
Ans.
Wrong answer = 7236 x 65 = 470340
7236
x 65
---------------
36180
+ 43416x
---------------
470340
---------------
Correct answer = 7236 x 56 = 405216
7236
x 56
-----------------
43416
+ 36180x
-----------------
405216
-----------------
Difference in answers
= 470340 – 405216
= 65,124
Q9. To stitch a shirt 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain?
Ans.
Cloth required to stitch one shirt
= 2 m 15 cm
= 2 x 100 cm + 15 cm (1 m = 100 cm)
= 215 cm
Length of cloth
= 40 m
= 40 x 100 cm
= 4000 cm
Number of shirts that can be stitched
= 4000 ÷ 215
18
________
215 | 4000
------- -215
--------
1850
-1720
--------
130
-------
Therefore 18 shirts can be stitched and 130 cm (1 m 30 cm) cloth will remain.
Q10. Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a can which cannot carry beyond 800 kg?
Ans.
The weight of one box
= 4 kg 500 g
= 4 x 1000 g + 500 g (1 kg = 1000 gm)
= 4500 g
Maximum load that can be loaded in van
= 800 kg
= 800 x 1000 g (1 kg = 1000 gm)
= 800000 g
Number of boxes = 800000 ÷ 4500
177
________
4500 | 800000
--------- -4500
----------
35000
-31500
----------
35000
-31500
----------
3500
----------
Therefore 177 boxes can be loaded in a can
Q11. The distance between the school and the house of a student’s house is 1 km 875 m. Every day she walks both ways. Find the total distance covered by her in six days.
Ans.
Distance between school and home
+ Distance between home and school
= 1.875 km + 1.875 km
= 3.750 km
Hence total distance covered in one day = 3.750 km
Distance covered in six days
= 3.750 x 6
= 22.500 km
Hence 22 km 500 m distance will be covered in six days.
Q12. A vessel has 4 litres and 500 ml of curd. In how many glasses each of 25 ml capacity, can it be filled?
Ans.
Capacity of curd in a vessel
= 4 litres 500 ml
= 4 x 1000 ml + 500 ml ( 1 litre = 1000 ml)
= 4500 ml
Capacity of one glass = 25 ml
Number of glasses can be filled
= 4500 ÷ 25
180
_______
25 | 4500
----- -25
------
200
-200
------
0
------
Hence 180 glasses can be filled by curd.
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